Notification texts go here: THIS SITE chemclip.com UNDER CONSTRUCTION (THIS SITE RECOVARY WITH IN 3-4 DAYS) Contact Us About

Quantum Chemistry Questions with solution| Rotational Spectroscopy

molecular spectroscopy, Rotational spectroscopy (or Microwave Spectroscopy), Rotational constant (B), Moment of inertia (I), Reduced mass
Please wait 0 seconds...
Scroll Down and click on Go to Link for destination
Congrats! Link is Generated

Hello, everyone today we will discuss a few questions with solutions under the quantum chemistry in the rigid rotator chapter. Correspond to examine molecular spectroscopy, Rotational spectroscopy (or Microwave Spectroscopy), Rotational constant (B), Moment of inertia (I), Reduced mass, etc.

we have to discuss the concept of quantum spectroscopy freely. Basic Knowledge or concept of rotational spectroscopy.

Principle of Rotational Spectroscopy:

In the rotational or microwave spectroscopy two energy lines (two transitional lines) distance is 2B. Where B is the rotational constant.

A rigid rotator undergoes transitions from one energy to another energy level. The allowed transitions state is ∆𝑙=∓1, that is the selection rule.

we have to consider the absorption of electromagnetic radiation, the molecule transition from quantum number l to l+1. The energy difference then is given below.


This is the image of the basic principle of microwave spectroscopy: quantum chemistry rigid rotator
The basic principle of microwave spectroscopy: quantum chemistry rigid rotator

Energy difference quantum number l to l+1 see in equation no. (i)

Using the Bohr frequency, compered the equation (i) and (ii) then we get the value of 𝜈,

Bohr Frequency 𝜈={ℎ/(4𝜋2 𝐼)}(𝑙+1). Where 𝑙=0, 1, 2, 3…..

We know that the Microwave spectroscopy frequency is 𝜈=2𝐵(𝑙+1). Where 𝑙=0, 1, 2, 3…..

we get the rotational constant 𝐵=ℎ/(8𝜋^2 𝐼). Where I= Moment of Inertia = (Reduced mass) × (Distance)2 =𝜇r2

Solve the problem of Quantum chemistry (Spectroscopy):

Now, solve the problem under microwave spectroscopy very easily if those basic principles are known. This suggestive question with a solution for CSIR UGC NET, GATE, and IIT JAM and correspond to other national level entrance exams. As an aspirant, this chapter of Quantum chemistry (spectroscopy -Rotational) read and solves this question.

Q.2. To a good approximation, the microwave spectrum of H35Cl consists of a series of equally spaced lines, separated by 6.26 × 1011 Hz. Calculate the bond length of H35Cl.

Option:

(A) 2.29 × 10-10 m (B) 2.29 × 10-8 m
(C) 1.29 × 10-10 m (D) 1.29 × 10-8 m

This is the image of Question.2 The basic principle of microwave spectroscopy: quantum chemistry rigid rotator
Question.2 The basic principle of microwave spectroscopy: quantum chemistry rigid rotator

Answer:

Option: (C) 1.29 × 10-10 m. Quantum chemistry question number two right answer is 1.29 × 10-10 m.

Hints:

We can see that the given question finds out the bond length of the diatomic molecule H35Cl. First of all, we know that the spacing of the lines in the microwave spectrum of H35Cl is 2B. Where B is the Rotational constant. The formula of the Rotational constant is

𝐵=ℎ/(8𝜋^2 𝐼) ……….(i)

Where I= Moment of Inertia = (Reduced mass) × (Distance)2 =𝜇r2 ………..(ii)

In case r is the Bond length of the given diatomic molecule H35Cl and 𝜇 is Reduced the mass of this diatomic molecule.

Reduced mass 𝜇 = (mH.mCl)/(mH + mCl) = (1 × 35)/(1+36) =35/36 =0.973 amu = 0.973 × 1.67 ×10-27 Kg.

𝜇 =1.62 × 10-27 Kg. Where 1amu = 1.67 ×10-27 Kg.

Now, the spacing of the lines in the microwave spectrum of H35Cl is 2B = 6.26 × 1011 Hz.

Put the value of 2B and Plank Constant h = 6.626 × 10-34 J.s in equation (i) we get the Moment of inertia I= 2.68 × 10-47 Kg. m2.

Finally, put the value of reduced mass 𝜇 =1.62 × 10-27 Kg and moment of inertia I= 2.68 × 10-47 Kg. m2 on equation (ii) we get the Bond length of H35Cl equal to 1.29 × 10-10 m.

Image solution:

Image solution of Question.2 microwave spectroscopy: quantum chemistry rigid rotator
Image solution of Question.2 microwave spectroscopy: quantum chemistry rigid rotator

Reference:

Few most popular and common books for Quantum chemistry. Read out the basic principle of quantum chemistry on spectroscopy below suggestion:

  • The best book for quantum chemistry is Donald A McQuarrie Viva’s student edition Quantum Chemistry. These are quality and quantitive books for chemistry students.
  • Quantum Chemistry Book by Ira N. Levine. It is a good rating book any time.
  • Molecular Quantum Mechanics Book by Peter Atkins. This book for basic knowledge of quantum chemistry postulates and concept of box particle.

Quantum-chemistry questions and answers pdf:

We have to provide quantum chemistry questions and answers pdf free to download. The PDF of the Basic principle of molecular spectroscopy (Quantum chemistry -spectroscopy). Click on the PDF file and free to download it.

Thank you for reading. Follow our official Facebook page: @chemclip or official Twitter handle: @chem_clip. Do you have any other queries regarding the article: leave a comment. Our team helps you as soon as possible.

Post a Comment

Cookie Consent
We serve cookies on this site to analyze traffic, remember your preferences, and optimize your experience.
Oops!
It seems there is something wrong with your internet connection. Please connect to the internet and start browsing again.
AdBlock Detected!
We have detected that you are using adblocking plugin in your browser.
The revenue we earn by the advertisements is used to manage this website, we request you to whitelist our website in your adblocking plugin.
Site is Blocked
Sorry! This site is not available in your country.